Percent of Americans Without Health Insurance by State, 2007–2008
Updated February 21, 2017 | Factmonster Staff
![Updated by an Factmonster Editor on February 21, 2017](/themes/ip/images/info-circle.png)
The following table lists the percent of Americans who did not have health-insurance coverage in 2007 and 2008. Data is listed by state.
State | 2007–2008 |
---|---|
Alabama | 11.9% |
Alaska | 19.0 |
Arizona | 18.9 |
Arkansas | 17.0 |
California | 18.4 |
Colorado | 16.1 |
Connecticut | 9.7 |
Delaware | 11.9 |
DC | 9.8 |
Florida | 20.1 |
Georgia | 17.7 |
Hawaii | 7.7 |
Idaho | 14.7 |
Illinois | 13.1 |
Indiana | 11.9 |
Iowa | 9.4 |
Kansas | 12.4 |
Kentucky | 14.8 |
Louisiana | 19.3 |
Maine | 9.6 |
Maryland | 12.9 |
Massachusetts | 5.4 |
Michigan | 11.7 |
Minnesota | 8.5 |
Mississippi | 18.3 |
Missouri | 12.6 |
Montana | 15.9 |
Nebraska | 12.6 |
Nevada | 18.0 |
New Hampshire | 10.3 |
New Jersey | 14.9 |
New Mexico | 23.1 |
New York | 13.6 |
North Carolina | 15.9 |
North Dakota | 10.9 |
Ohio | 11.6 |
Oklahoma | 15.9 |
Oregon | 16.5 |
Pennsylvania | 9.7 |
Rhode Island | 11.3 |
South Carolina | 16.1 |
South Dakota | 11.3 |
Tennessee | 14.7 |
Texas | 25.1 |
Utah | 13.0 |
Vermont | 10.2 |
Virginia | 13.6 |
Washington | 11.8 |
West Virginia | 14.6 |
Wisconsin | 8.9 |
Wyoming | 13.6 |
United States | 15.3 |
Source: U.S. Census Bureau.